Answer:
[tex]54.75^\circ[/tex]
Step-by-step explanation:
Formula for horizontal distance or range is given as:
[tex]s=\dfrac{2v_i^2sin\theta cos\theta}{g}[/tex]
Where
[tex]v_i[/tex] is the initial velocity
[tex]\theta[/tex] is the angle with horizontal at which the projectile was thrown
[tex]g[/tex] is the acceleration due to gravity.
Given,
Initial velocity, [tex]v_i[/tex] = 60 m/s
Range, [tex]s[/tex] = 300 m
To find: [tex]\theta = ?[/tex]
Solution:
Using the formula as stated above:
[tex]300=\dfrac{2\times 60^2sin\theta cos\theta}{9.8}\\\Rightarrow 2sin\theta cos\theta =\dfrac{300\times 9.8}{3600}\\\Rightarrow sin2\theta =0.81666\\\Rightarrow \theta \approx \bold{54.75^\circ}[/tex]
Firing angle [tex]54.75^\circ[/tex] will produce a range of 300 m.
