Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔGo:reaction A: glucose-1-phosphate rightarrow glucose-6-phosphate, ΔGo = -7.28 kJ/mol reaction B: fructose-6-phosphate rightarrow glucose-6-phosphate, ΔGo = -1.67 kJ/molCalculate for the isomerization of glucose-1-phosphate to fructose-6-phosphate.Calculate the equilibrium constant K for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 K.

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Xema8 Xema8 · Answer 1 · 2020-11-24T05:03:38+01:00

Answer:

Explanation:

glucose-1-phosphate → glucose-6-phosphate, ΔGo = -7.28 kJ/mol

fructose-6-phosphate → glucose-6-phosphate, ΔGo = -1.67 kJ/mol

subtracting the equation

glucose-1-phosphate - fructose-6-phosphate = 0 , ΔGo = -7.28 - ( -1.67 ) kJ / mol

glucose-1-phosphate = fructose-6-phosphate ΔGo = - 5.61 kJ / mol

- ΔGo = RT lnK

5.61 x 10³ = 8.31 x 298 x lnK

lnK = 2.265

K = 9.63 .