Answer:
I = 6.42 A
Explanation:
Given that,
Potential difference, V = 0.9 V
Length of the wire, l = 1.5 m
Area of cross section, [tex]A=0.6\ mm^2=6\times 10^{-7}\ m^2[/tex]
We need to find the current in the wire. Let I is current. We can find it using Ohm's law as follows :
V = IR
Where R is the resistance of the wire
[tex]I=\dfrac{V}{R}\\\\I=\dfrac{V}{\rho \dfrac{l}{A}}\\\\I=\dfrac{0.9}{5.6\times 10^{-8}\times \dfrac{1.5}{6\times 10^{-7}}}\\\\I=6.42\ A[/tex]
So, the current in the wire is 6.42 A.
