If you measure the properties of an unknown material and find that it has a density of 3.13 g/cm3 (+/- 0.1 g/cm3) and boils at 1415 °C (+/- 5 ºC), which material would it most likely be?

A) Potassium iodide
B) Sulfur
C) Iodine
D) Lead nitrate
E) Copper chloride
F) Sodium chloride
G) Copper nitrate

For a substance to boil at 1415 °C shows the substance is an electrovalent/ionic substance (hence the elements are not the answer). Electrovalent/ionic substances are characterized by high melting and boiling points. Also, with a density of 3.13 g/cm³ (with a +/- 0.1 g/cm³), the correct answer is potassium iodide. This is because potassium iodide has a density of 3.12 g/cm³ (which is - 0.1 g/cm³). It should also be noted that pure potassium iodide boils at 1,330 °C, however the presence of impurities could increase the boiling point of the salt, thus an impure potassium iodide could have a density of 3.12 g/cm³ and a temperature around 1415 °C

Cricetus Cricetus · Answer 2 · 2021-11-24T14:28:30+01:00

"Potassium iodide" would it most likely be. A further explanation is provided below.

Given values are:

Density,

3.13 g/cm³

Boiling point,

1415 C

Density can be change by,

+/-0.1 g/cm³

Uncertainty in temperature,

+/-5°C

We can take the value of density from:

3.03 (3.13-0.1) to,
3.23 (3.13+0.1)

We can take the value of temperature from:

1410 C (1415-5) to,
1420 C (1415+5)

After checking the ranges, we find "Potassium iodide" have density as well as temperature in our range.

Thus the above answer is right.

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