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Lanuel

Answer:

Power = 2.45Kw or 2450 Watts.

Explanation:

Given the following data;

Mass, m = 250kg

Height, h = 2m

Time, t = 2secs

We know that acceleration due to gravity, g is equal to 9.8m/s²

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

[tex] Power = \frac {Energy}{time} [/tex]

But Energy = mgh

Substituting into the equation, we have

[tex] Power = \frac {mgh}{time} [/tex]

[tex] Power = \frac {250*9.8*2}{2} [/tex]

[tex] Power = \frac {4900}{2} [/tex]

Power = 2450 Watts

To convert to kilowatt (Kw), we would divide by 1000

Power = 2450/1000

Power = 2.45Kw.

Therefore, the average power output of the weightlifter is 2.45 Kilowatts.

The average power output of the weight lifter who can lift the given mass is 2450 Watts.

Given the data in the question;

  • Mass; [tex]m = 250kg[/tex]
  • Displacement; [tex]d = 2.0m[/tex]
  • Time taken; [tex]t = 2.0s[/tex]

Power is the amount of energy transferred per unit time. It is expressed as:

[tex]P = \frac{W}{\delta t}[/tex]

Where W is work done and t is elapsed time.

So, we find the work done

Work done = Force × Displacement

Since Force = Weight = m × g

Where g is acceleration due to gravity ( [tex]9.8m/s^2[/tex] )

Hence

[tex]Work\ done = mg * d\\\\Work\ done = 250kg\ *\ 9.8m/s^2\ *\ 2.0m\\\\Work\ done = 4900kg.m^2/s^2[/tex]

We substitute our value into the previous equation

[tex]P = \frac{Work\ done}{\delta t}\\\\P = \frac{4900kg.m^2/s^2}{2.0s} \\\\P = 2450kg.m^2/s^3\\\\P = 2450J/s\\\\P = 2450W[/tex]

Therefore, the average power output of the weight lifter who can lift the given mass is 2450 Watts.

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