Answer:
827.85 torr
Explanation:
Given that,
Pressure, P₁ = 610 torr
Temperature, T₁ = 28°C
We need to find the new pressure if the new temperature is 38°C and if the volume remained the same. Using Gay-lussac's law,
[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]
We need to find P₂.
[tex]P_2=\dfrac{P_1T_2}{T_1}\\\\P_2=\dfrac{610\times 38}{28}\\\\P_2=827.85\ \text{torr}[/tex]
So, the new pressure is 827.85 torr.
