Mr. Hamilton decorates his U.S. History classroom by putting up pictures of the presidents. The wall is 9.75 feet long. In the center, there is a window that is 5 3/4 feet long. ​ Each president's picture is 6 inches wide. If the pictures are placed side by side on either side of the window, how many pictures can he fit on this wall?

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Answer:

8 pictures

Step-by-step explanation:

Given

[tex]Window = 5\frac{3}{4}ft[/tex]

[tex]Wall = 9.75ft[/tex]

[tex]Pictures = 6\ inches[/tex]

Required

Determine the number of pictures

First, we need to calculate the length of the available space

This is calculated by subtracting the width of the window from the width of the wall.

[tex]Space = Wall - Window[/tex]

[tex]Space = 9.75 - 5\frac{3}{4}[/tex]

Convert fraction to decimal

[tex]Space = 9.75 - 5.75[/tex]

[tex]Space = 4ft[/tex]

Since, the pictures are placed side by side.

This means that, there's no empty space between them.

Number of pictures is:

[tex]Number = \frac{Space}{Pictures}[/tex]

[tex]Number = \frac{4\ ft}{6\ in}[/tex]

Convert feet to inches

[tex]Number = \frac{4 * 12\ in}{6\ in}[/tex]

[tex]Number = \frac{48\ in}{6\ in}[/tex]

[tex]Number = \frac{48}{6}[/tex]

[tex]Number = 8[/tex]

Hence, 8 pictures can fit the wall

Answer:

8 pictures

Step-by-step explanation:

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