23) What is the equation of the line below?
24) What is the equation for the table below?

First of all, you need to find the slopes of each. To do this, we need to take 2 points from each and plug them into y2 -y1/ x2 - x1.
For the graph we will take the points given (0,5) (4,0)
0 - 5 / 4 -0 = -5/4 = your slope for the graph
For the table, we will take the first three points. (-1,-1) (0,3) (1,7)
7 - 3 / 1 - 0 = 4 / 1 = 4
3 - - 1 / 0 - - 1 = 4 / 1 = 4
Therefore, the slope of the table is 4.
Now, for the y-intercepts.
These are normal be the points (0, y)
For the graph this would be (0,5) and for the table it would be (0,3)
Slope - intercept form = y = mx + b, where m is the slope and b is the y-intercept form.
Soo,
For the graph, it would be;
Y = -5/4x + 5
And for the table, it would be;
Y = 4x + 3