Value of [tex]p[/tex] is [tex]\frac{3}{2}[/tex]
In inverse variation, as one number increases, the other decreases and as one number decreases, the other increases.
That is [tex]xy=k[/tex] where [tex]k[/tex] is a constant.
Put values of [tex]x,y[/tex] as [tex]3,5[/tex] respectively.
[tex]3(5)=k[/tex]
[tex]15=k[/tex]
So, [tex]xy=15[/tex]
Now put values of [tex]x,y[/tex] as [tex]10,p[/tex] respectively.
[tex]10p=15[/tex]
[tex]p=\frac{15}{10}[/tex]
[tex]=\frac{3}{2}[/tex]
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