A marble rolls off a table from a height of 1.5 meters. Approximately how much time was the marble in the air?
O 1.1 seconds
O 0.78 seconds
O 0.55 seconds
O 0.2 seconds

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Muscardinus Muscardinus · Answer 1 · 2020-11-26T11:53:00+01:00

Answer:

t = 0.55 s

Explanation:

Given that,

Height of the marble, h = 1.5 m

We need to find the time for which the marble is in air. Let the time is t. Using second equation of motion to find it as follows :

[tex]h=ut+\dfrac{1}{2}at^2[/tex]

Here, u = 0 and a = g

[tex]h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\cdot1.5}{9.8}}\\\\t=0.55\ s[/tex]

So, the marble is in air for 0.55 s. Hence, the correct option is (c).