A science teacher ordered S2278 worth of microscopes and dissection kits for the new science lab. A total of
26 microscopes and 56 dissection kits were ordered. A microscope costs three times as much as a dissection
kit. Write a system of linear equations that represents this situation. What is the cost of each item?

Respuesta :

Answer:

[tex]26M + 56D = 2278[/tex] ---- equation 1

[tex]M = 3D[/tex] ---- equation 2

A microscope costs S51 and a dissection kit costs S17

Step-by-step explanation:

Given

Represent microscope with M and Dissection kits with D

Cost:

[tex]M = 3D[/tex]

[tex]Total = 2278[/tex]

Required

Represent as an equation:

To do this, we represent the equation in terms of cost and quantity

In terms of cost, we have:

[tex]26M + 56D = 2278[/tex] ---- equation 1

and

[tex]M = 3D[/tex] ---- equation 2

Substitute 3D for M in equation 1

[tex]26*3D + 56D = 2278[/tex]

[tex]78D + 56D = 2278[/tex]

[tex]134D = 2278[/tex]

Divide both sides by 134

[tex]D = \frac{2278}{134}[/tex]

[tex]D = 17[/tex]

Substitute 17 for D in [tex]M = 3D[/tex]

[tex]M = 3 * 17[/tex]

[tex]M = 51[/tex]

Hence:

A microscope costs S51 and a dissection kit costs S17

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