Answer:
The velocity of cart B after the collision is 1.29 m/s.
Explanation:
We can find the velocity of cart B by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{A}v_{A_{i}} + m_{B}v_{B_{i}} = m_{A}v_{A_{f}} + m_{B}v_{B_{f}} [/tex]
Where:
[tex]m_{A}[/tex] is the mass of cart A = 600 g = 0.6 kg
[tex]m_{B}[/tex] is the mass of cart B = 200 g = 0.2 kg
[tex]v_{A_{i}}[/tex] is the inital velocity of cart A = 0.7 m/s
[tex]v_{A_{f}}[/tex] is the final velocity of cart A = 0.27 m/s
[tex]v_{B_{i}}[/tex] is the initial velocity of cart B = 0
[tex]v_{B_{f}}[/tex] is the final velocity of cart B =?
Taking the left direction as the positive horizontal direction:
[tex] 0.6 kg*0.7 m/s + 0 = 0.6 kg*0.27 m/s + 0.2 kg*v_{B_{f}} [/tex]
[tex] v_{B_{f}} = 1.29 m/s [/tex]
Therefore, the velocity of cart B after the collision is 1.29 m/s.
I hope it helps you!
