Considering the reaction stoichiometry, 22.2 moles of Fe(OH)₂ are required to produce 7.4 moles of Fe₃(PO₄)₂.
The balanced reaction is:
3 Fe(OH)₂ + 2 H₃PO₄ → Fe₃(PO₄)₂ + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Then you can apply the following rule of three: if by reaction stoichiometry 1 mole of Fe₃(PO₄)₂ requires 3 moles of Fe(OH)₂, 7.4 moles of Fe₃(PO₄)₂ require how many moles of Fe(OH)₂?
[tex]amount of moles of Fe(OH)_{2} =\frac{7.4 moles of Fe_{3} (PO_{4} )_{2} x3moles of Fe(OH)_{2} }{1mole of Fe_{3} (PO_{4} )_{2} }[/tex]
amount of moles of Fe(OH)₂= 22.2 moles
Finally, 22.2 moles of Fe(OH)₂ are required to produce 7.4 moles of Fe₃(PO₄)₂.
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