Answer:
v = 12.3 m / s
Explanation:
This is an exercise in kinetics in one dimension
v² = v₀² + 2 a x
In this exercise they tell us that the initial velocity is (v₀ = 13 m / s), the acceleration is a = -0.95 m / s2 and the distance x = 9.2 m
we substitute
v = √ (13 2 - 2 0.95 9.2)
v = 12.3 m / s
note that as the acceleration is negative the vehicle is stopping
