Yield of reaction = 80%
Further explanation
Reaction
Cu(NO₃)₂ (aq) + Na₂S (aq) ⇒ 2 NaNO₃ (aq) + CuS (s)
mol Cu(NO₃)₂ :(MW 187,56 g/mol)
[tex]\tt \dfrac{469}{187.56}=2.5[/tex]
mol Na₂S :(MW 78,0452 g/mol)
[tex]\tt \dfrac{156}{78.0452}=2[/tex]
Limiting reactant⇒Na₂S( 2 < 2.5)
mol of NaNO₃ (MW = 84,9947 g/mol)
[tex]\tt 2\times 2=4[/tex]
mass NaNO₃ (theoretical)
[tex]\tt 4\times 84.9947=339.979~g[/tex]
[tex]\tt \dfrac{272}{339.979}=0.8\rightarrow=80\%[/tex]
