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What mass of water can be heated from 10.0 C to 38.0 Celsius by addition of 3,500j? (Specific heat capacity of water is 4.18 j/g C)

Respuesta :

ardni313

Mass of water : 29.904 g

Further explanation

Heat can be formulated

Q=m.c.Δt

Q, heat, J

m,mass, g

c, specific heat, j/g C

Δt,temperature, C

  • Δt,temperature

[tex]\tt 38-10=28^oC[/tex]

  • mass of water

[tex]\tt m=\dfrac{Q}{c.\Delta t}\\\\m=\dfrac{3500}{4.18\times 28}\\\\m=29.904~g[/tex]

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