Answer:
a. 53.3°C.
b. Percent error for both students is 53.3°C
c. Both students are equal in accuracy.
2nd student is most precise
Explanation:
The percent error is defined as:
|M - T| / T * 100
Where M is measurement,
and T is theoretical value
a. To obtain the average of both measurements we need to sum the measurements and divide these in the number of measurements:
51.5°C+53.5°C+55.0°C+52.3°C+54.2°C+52.3°C+53.2°C+54.0°C+53.5°C / 9
= 53.3°C
b. Percent error for 1st student:
51.5°C+53.5°C+55.0°C+52.3°C+54.2°C / 5 = 53.3°C
|53.3°C - 53.0°C| / 53°C * 100
0.57%
Percent error for 2nd student:
52.3°C+53.2°C+54.0°C+53.5°C / 4 = 53.3°C
|53.3°C - 53.0°C| / 53°C * 100
0.57%
c. Now, precision is how close are the measurements to each other and the accuracy how close are the measurements to the theoretical value:
The accuracy is obtained with percent error, the lower percent error the most accurate measurement. That means:
both students are equal in accuracy.
And precision is obtained with relative standard desviation.
Desviation standard / Average * 100
(We can solve the standard desviation in a scientific calculator):
1st student:
2.65%
2nd student:
1.34%
The lower RSD the most precise measurements.
