hcyoung416 hcyoung416

19-11-2020
Mathematics

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An arithmetic sequence has a common difference of five and begins with the number twelve. What would be the 26th term in the sequence?

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johnobel59 johnobel59

19-11-2020

Answer:

The first term a = 12

common difference d = 5

nth term Tn = a + (n-1)d

26th term = 12 + (25-1)5

= 12 + (24)5

= 12 + 120

26th term = 132

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