Form a polynomial whose zeros and degree are given.
Zeros: -2, 2, 9; degree: 3
Type a polynomial with integer coefficients and a leading coefficient of 1 in the box below.

Respuesta :

Answer:

the polynomial is: [tex]\mathbf{x^3-9x^2-4x+36=0}[/tex]

Step-by-step explanation:

We need to form a polynomial whose zeros are:

-2,2,9

We can write them as: x=-2, x=2 and x=9

x+2=0, x-2=0 , x-9=0

(x+2)(x-2)(x-9)=0

Now multiplying all terms:

[tex](x(x-2)+2(x-2))(x-9)=0\\(x^2-2x+2x-4)(x-9)=0\\(x^2-4)(x-9)=0\\x^2(x-9)-4(x-9)=0\\x^3-9x^2-4x+36=0[/tex]

So, the polynomial is: [tex]\mathbf{x^3-9x^2-4x+36=0}[/tex]

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