Answer:
6.02 x 10²⁰ molecules
Explanation:
Given parameters:
Volume of nitrogen = 120cm³
Unknown:
Mass of Nitrogen = ?
Number of molecules present in it = ?
Solution:
At STP;
1 mole of a substance contains 22.4dm³ particles
100cm³ = 1dm³
24cm³ will give 0.024dm³
22.4dm³ of particles are in 1 mole of substances at STP
0.024dm³ of particles will contain [tex]\frac{0.024}{24}[/tex] = 0.001mole
Mass of Nitrogen = Number of moles x molar mass
molar mass of nitrogen = 14g/mol
Mass of nitrogen = 0.001 x 14 = 0.014g
Number of molecules present;
1 mole of a substance contains 6.02 x 10²³ molecules
0.001 mole of Nitrogen will contain 0.001 x 6.02 x 10²³ = 6.02 x 10²⁰
6.02 x 10²⁰ molecules
