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A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?

Respuesta :

whitneytr12

Answer:

The angular velocity of the propeller is 2.22 rad/s.

Explanation:

The angular velocity (ω) of the propeller is:  

[tex] \omega = \frac{\Delta \theta}{\Delta t} [/tex]                              

Where:

θ: is the angular displacement = 10.6 revolutions

t: is the time = 30 s

[tex] \omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s [/tex]

Therefore, the angular velocity of the propeller is 2.22 rad/s.

I hope it helps you!

Cricetus

The angular velocity will be "2.22 rad/s".

Given:

Angular displacement,

  • [tex]\Theta = 10.6[/tex]

Diameter,

  • 3 m

Time,

  • [tex]\Delta t = 30 \ s[/tex]

Now,

The angular velocity will be:

→ [tex]\omega = \frac{\Delta \Theta}{\Delta t}[/tex]

By putting the values, we get

       [tex]= \frac{10.6\times \frac{2 \pi rad}{1 \ rev} }{30 \ s}[/tex]

       [tex]= 2.22 \ rad/s[/tex]

Thus the response above is right.

Learn more about velocity here:

https://brainly.com/question/14370151

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