Answer:
49° approx.
Step-by-step explanation:
Step one:
given
The distance of the ship from the base= 1.3km
Height of the cliff= 150m= 1.5km
Step two:
Required
angle of depression
Applying SOH CAH TOA
The opposite is to the angle of depression is the height which is 1.5km
The distance of the ship from the foot of the cliff is the adjacent which is 1.3km
Tan ∅=Opp/Adj
Tan ∅=1.5/1.3
∅=Tan-1 1.5/1.3
∅=Tan-1 1.153
∅=49.06
49° approx.
