3.1
power
Every day a certain household uses a 4.4 KW electric stove for 70 minutes, seven 150 W light bulbs for 7
hours each and miscellaneous appliances amounting to 1.8 KW/h. The 4 KW hot water cylinder switches
on for a total of 120 minutes during the day. If electricity cost 50c a KW/h. what is the monthly electricity
bill. (5 marks)

Respuesta :

Answer:

The value is  [tex]C = 30729\ c[/tex]

Explanation:

From the question we are told that

  The power rating of the stove is  [tex]P = 4.4 KW = 4.4 *10^{3} \ W[/tex]

   The duration of its use everyday is [tex]t_1 = 70 \ minutes = 1.167 \ hours[/tex]    

    The rating of the light bulbs is [tex]P_2' = 150 W[/tex]

   The number is [tex]n = 7[/tex]

   The power rating of the total  bulb is  [tex]P_2 = 7 * 150 = 1050 \ W[/tex]

    The duration of its use everyday is  [tex]t_2 = 7 hours[/tex]

    The power rating of miscellaneous appliance [tex]P_3 = 1.8 \ KW = 1.8 *10^{3} \ W[/tex]

    The duration of its use everyday is [tex]t_3 = 1 hour[/tex]

     The power rating of hot water [tex]P = 4 KW = 4 *10^{3} \ W[/tex]

      The duration of its use everyday is [tex]t_4 = 120 \ minutes = 2 hours[/tex]

Generally the total electrical energy used in 1 month is mathematically represented as

    [tex]E = P_1 * t_1 * 30 + P_2 * t_2 * 30 + P_3 * t_3 * 30+ P_4 * t_4 * 30[/tex]

=>  [tex]E = 4.4*10^{3} * 1.167 * 30 + 1050 * 7 * 30 + 1.8 *1 * 30+ 4*10^{3} * 2 * 30[/tex]

=>  [tex]E = 614598 \ W \cdot h[/tex]

=>   [tex]E = 614.6 \ K W \cdot h[/tex]

Generally the monthly electricity  bill is mathematically represented as

    [tex]C = 614.6 * 50[/tex]

=> [tex]C = 30729\ c[/tex]

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