contestada

What is the magnitude of the total acceleration of the tip of a 1.20-m airplane propeller that is moving with an angular speed of 35.0 rad/s and undergoing an angular acceleration of 11.0 rad/s2?
a. 138 m/s2
b. 42 m/s2
c. 145 m/s2
d. 151 m/s^2

Respuesta :

Answer:

a = 13.2 m / s²

Explanation:

For this exercise let's use that the angular and linear variables are related

     

they relate it linearly

          a = α r

          a = 11.0 1.20

          a = 13.2 m / s²

     

the centripetal related

          ac = r w²

          ac = 1.20 35²

          ac = 1470 m / s²

we can see that the answers are not close to the real answer

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE