Answer:
* [tex]HI (aq) +NaOH (aq) \rightarrow NaI(aq)+H_2O(l)[/tex]
* [tex]H_2CO_3 (aq) + Sr(OH)_2\rightarrow SrCO_3(s)+2H_2O(l)[/tex]
* [tex]Ca(OH)_2 (s) +H_2SO_4 (aq)\rightarrow CaSO_4(aq)+2H_2O(l)[/tex]
Explanation:
Hello!
In this case, since neutralization chemical reactions are carried out when an acid and a base react to produce a salt and water, for the first reaction, HI (aq) and NaOH (aq), we can write:
[tex]HI (aq) +NaOH (aq) \rightarrow NaI(aq)+H_2O(l)[/tex]
Whereas the salt, sodium iodide remains aqueous and water liquid. Next, when carbonic acid and strontium hydroxide react, strontium carbonate as the salt precipitates out and water is also produced:
[tex]H_2CO_3 (aq) + Sr(OH)_2\rightarrow SrCO_3(s)+2H_2O(l)[/tex]
Finally, when calcium hydroxide and sulfuric acid react, the compound calcium sulfate as the salt and water are produced as shown below:
[tex]Ca(OH)_2 (s) +H_2SO_4 (aq)\rightarrow CaSO_4(aq)+2H_2O(l)[/tex]
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