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Suppose we wish to use a 8.0 m iron bar to lift a heavy object by using it as a lever. If we place the pivot point at a distance of 1.0 m from the end of the bar that is in contact with the load and we can exert a downward force of 562 N on the other end of the bar, find the maximum load that this person is able to lift (pry) using this arrangement (neglect the mass of the bar in this problem).

Respuesta :

Answer:

W = 3934 N ,     m = 401.43 kg

Explanation:

This problem can be solved using the rotational equilibrium relation, where we place the reference system at the pivot point and assume that the counterclockwise turns are positive.

     ∑τ = 0

     F 7 - W 1 = 0

    W = F 7/1

     W = 562 7

     W = 3934 N

   

W = mg

     m = W / g

     m = 3934 / 9.8

     m = 401.43 kg

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