Answer:
241,920 different ways
Step-by-step explanation:
We have 6 vowels, but A repeats twice and I repeats three times, so the number of ways in which each can either start or end the word:
³P₂ = 3! / (3 - 2)! = 6 / 1 = 6 ways
You can start words with A, E or I, or end the words with A, E, or I.
the remaining 8 consonants can be arranged in 8! ways = 40,320 ways
total number of ways that the letters can be arranged = 6 x 40,320 = 241,920 different ways
The total number of ways the researcher arrange the word CALLITRICHIDAE that start or end with vowels is 6 ways and this can be determined by using the given data.
Given :
Word -- CALLITRICHIDAE
The following steps can be used in order to determine the total number of ways the researcher arrange the word CALLITRICHIDAE:
Step 1 - First, calculate the total number of vowels in the given word CALLITRICHIDAE.
Total vowels = 6
Step 2 - Now, determine the total number of times a letter repeat in the word CALLITRICHIDAE.
So, the letter A appears 2 times and letter I appears 3 times in the word CALLITRICHIDAE.
Step 3 - Now, evaluate the total number of ways the word CALLITRICHIDAE is arranged:
[tex]\rm Total \;Number\; of\; Ways=\; ^3P_2 = \dfrac{3!}{(3-2)!}=6[/tex]
For more information, refer to the link given below:
https://brainly.com/question/1216161
