Answer:
3.63×20^-3V
Explanation:
circular copper loop is placed perpendicular to a uniform magnetic field of 0.75 T. Due to external forces, the area of the loop decreases at a rate of 7.26 × 10^–3 m^2 /s. Determine the induced emf in the loop.
From Faraday-Newmann-Lenz law, the induced emf in the loop is given b
e=- Δθ/Δl
Δθ/Δl= rate of variation of the magnetic flux through the loop.
magnetic flux through the loop = BA
B = magnetic field
A i=area of the loop.
symbol: Φ
Since the magnetic field is constant, the variation of flux can be writing as
e=- B ΔA/Δt
=7.26 × 10^–3 m^2 /s × 0.5T
=3.63×20^-3V
