Respuesta :

Space

Answer:

[tex]x=-2.35078, 0.850781[/tex]

General Formulas and Concepts:

Pre-Algebra

  • Order of Operations: BPEMDAS

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: [tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Step-by-step explanation:

Step 1: Define equation

-3x = 2x² - 4

Step 2: Rewrite into Standard Form

0 = 2x² + 3x - 4

Step 3: Define variables

a = 2

b = 3

c = -4

Step 4: Find x

  1. Substitute:                    [tex]x=\frac{-3\pm\sqrt{3^2-4(2)(-4)} }{2(2)}[/tex]
  2. Evaluate:                       [tex]x=\frac{-3\pm\sqrt{9-4(2)(-4)} }{2(2)}[/tex]
  3. Multiply:                        [tex]x=\frac{-3\pm\sqrt{9+32} }{4}[/tex]
  4. Add:                              [tex]x=\frac{-3\pm\sqrt{41} }{4}[/tex]
  5. Evaluate:                      [tex]x=\frac{-3\pm6.40312}{4}[/tex]
  6. Evaluate:                      [tex]x=-2.35078, 0.850781[/tex]

And we have our final answer!

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