Look at a z table and look up z = 1.34.
The number associated with z = 1.34 is 0.9099
The p value is that value subtracted from 1.
P value = 1 − 0.9099 = 0. 0901
The p - value for the test statistic should be considered as the 0.0901.
Since there is null and alternative hypotheses
so here we look at the z table and then the value should be 1.34
So, the value of z in 1.34 should be 0.9099
So, here the p-value should be
= 1 - 0.9099
= 0.0901
hence, The p - value for the test statistic should be considered as the 0.0901.
learn more about null here: https://brainly.com/question/18831983
