Answer:
[tex]Q=210.8kJ[/tex]
Explanation:
Hello!
In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:
[tex]Q=m\Delta H_{vap}[/tex]
In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:
[tex]Q=155g*1360J/g\\\\Q=210.8kJ[/tex]
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