Answer:
The zero of the line is (2,0)
Step-by-step explanation:
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as:
[tex]\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
We are given the points (1,-3) and (4,6). Substituting:
[tex]\displaystyle y+3=\frac{6+3}{4-1}(x-1)[/tex]
Operating:
[tex]\displaystyle y+3=\frac{9}{3}(x-1)[/tex]
[tex]y+3=3(x-1)[/tex]
The zero of this line can be found by making y=0 and solving for x:
0+3=3(x-1)
3=3x-3
Adding 3:
6=3x
Solving:
x = 2
The zero of the line is (2,0)
