Answer:
h = 65.021 m
Explanation:
Given that,
Initial velocity of a baseball, u = 17 m/s
It lands 2.3 seconds later.
We need to find the height of the building. Let it is h. It can be calculated using second equation of motion as follows :
[tex]h=ut+\dfrac{1}{2}at^2[/tex]
here, a = g
[tex]h=17(2.3)+\dfrac{1}{2}\times 9.8\times 2.3^2\\\\=65.021\ m[/tex]
So, the building is 65.021 m tall.
