Answer:
3.34 kJ
Explanation:
m = Mass of ice = 10 g
L = Latent heat of ice = 334 J/g
Heat required to melt the ice at 0°C is given by
[tex]Q=mL[/tex]
[tex]\Rightarrow Q=10\times 334[/tex]
[tex]\Rightarrow Q=3340\ \text{J}[/tex]
[tex]\Rightarrow Q=3.34\times 10^3\ \text{J}[/tex]
[tex]\Rightarrow Q=3.34\ \text{kJ}[/tex]
The heat required to melt the required amount of ice is 3.34 kJ
