Tank has an average bearing pressure of 105 kPa. Ground water is deep. Calculate the total, pore and effective stress before tank loading and with tank

Respuesta :

Answer:

Hello your question is incomplete attached below is the complete question

answer :

A) At 8 meters below center

Total stress = 228.827 KN/m^2

pore water pressure = 0 KN/m^2

effective stress = 228.827 - 0 = 228.827 KN/m^2

B) At 8 meters below tank edge

Total stress = 186.289 KN/m^2

pore water stress = 0 Kn/m^2

effective stress = 186.289 - 0 = 186.289 KN/m^2

Explanation:

Given data :

Diameter = 21 m

radius = 21 / 2 = 10.5 m

soil moist = 18.4 KN/cubic meter

Average bearing pressure = 105 kPa

i) Before Loading Tank

 Total stress = 8 * 18.4 = 147.2 KN/m^2

 Pore pressure = 0 KN/m^2

 Effective stress = 147.2 - 0 = 147.2 KN/m^2

ii) After loading Tank

  No change occurs

A) At 8 meters below center

Total stress = 228.827 KN/m^2

pore water pressure = 0 KN/m^2

effective stress = 228.827 - 0 = 228.827 KN/m^2

B) At 8 meters below tank edge

Total stress = 186.289 KN/m^2

pore water stress = 0 Kn/m^2

effective stress = 186.289 - 0 = 186.289 KN/m^2

attached below is the detailed solution

Ver imagen batolisis
Ver imagen batolisis
ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE