Respuesta :
Answer:
Explained below.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
[tex]\mu_{\hat p}=p[/tex]
The standard deviation of this sampling distribution of sample proportion is:
[tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]
A random sample of n = 658 items is sampled randomly from this population.
As the sample size is large, i.e. n = 658 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample proportion by a Normal distribution.
Compute the mean and standard deviation as follows:
[tex]\mu_{\hat p}=0.61\\\\\sigma_{\hat p}=\sqrt{\frac{0.61(1-0.61)}{658}}=0.019[/tex]
(a)
Compute the probability that the sample proportion is greater than 0.63 as follows:
[tex]P(\hat p>0.63)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}>\frac{0.63-0.61}{0.019})\\\\=P(Z>1.05)\\\\=1-P(Z<1.05)\\\\=1-0.85314\\\\=0.14686\\\\\approx 0.1469[/tex]
(b)
Compute the probability that the sample proportion is between 0.60 and 0.66 as follows:
[tex]P(0.60<\hat p<0.66)=P(\frac{0.60-0.61}{0.019}<\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}<\frac{0.66-0.61}{0.019})\\\\=P(-0.53<Z<2.63)\\\\=P(Z<2.63)-P(Z<-0.53)\\\\=0.99573-0.29806\\\\=0.69767\\\\\approx 0.6977[/tex]
(c)
Compute the probability that the sample proportion is greater than 0.592 as follows:
[tex]P(\hat p>0.592)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}>\frac{0.592-0.61}{0.019})\\\\=P(Z>-0.95)\\\\=P(Z<0.95)\\\\=0.82894\\\\\approx 0.8289[/tex]
(d)
Compute the probability that the sample proportion is between 0.57 and 0.60 as follows:
[tex]P(0.57<\hat p<0.60)=P(\frac{0.57-0.61}{0.019}<\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}<\frac{0.60-0.61}{0.019})\\\\=P(-2.11<Z<-0.53)\\\\=P(Z<-0.53)-P(Z<-2.11)\\\\=0.29806-0.01743\\\\=0.28063\\\\\approx 0.2806[/tex]
(e)
Compute the probability that the sample proportion is less than 0.51 as follows:
[tex]P(\hat p<0.51)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}<\frac{0.51-0.61}{0.019})\\\\=P(Z<-5.26)\\\\=0[/tex]
