Answer:
t = 0.6933 s
Explanation:
This is a rotational kinematics exercise, let's find the angular acceleration of the wheel
w² = w₀² + 2 α θ
α = (w² - w₀²) / 2 θ
Let's reduce the angles to the SI system
θ = 16 rev (2π rad / 1 rev) = 32π rad
let's calculate
α = (105² - 185²) / (2 32π)
α = -115.39 rad / s²
now let's use the relation
w = w₀ + α t
t = (w- w₀) /α
t = (105 - 185) / (- 115.39)
t = 0.6933 s
