SSS congruence of triangles is proved when all three sides of considered two triangles are congruent(that is, of equal measures).
Thus, the needed answer is:
Line segment DF is congruent to line segment AC
or [tex]\overline{DF} \cong \overline{AC}[/tex]
What is SSS congruence of triangles?
If two considered triangles have corresponding side pairs congruent(for all three sides), then both the triangles are congruent. This proof of congruence is triangle is done by SSS congruence of triangles (Side Side Side congruence)
Since it is given that the sides CB and FE are congruent,
and since it is given that sides AB and DE are congruent too,
thus, for SSS congruence of both considered triangles, we need the third side pair of the given triangles to be congruent too.
Thus, we need the line segment DF congruent to the line segment AC.
We can write it symbolically as:
[tex]\overline{DF} \cong \overline{AC}[/tex] (remember that order doesn't matter here. You could've written [tex]\overline{AC} \cong \overline{DF}[/tex] too.)
Learn more about SSS congruence of triangles here:
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