What is the equation of a line that passes through (-6,2) and has a slope of ‘-(1)/(2)’?

Answer:
y=[tex]-\frac{1}{2}[/tex]x -1
Step-by-step explanation:
y=mx+c
y=[tex]-\frac{1}{2}[/tex]x +c
substitute (-6;2)
2=[tex]-\frac{1}{2}[/tex](-6)+c
2=3+c
2-3=c
c=-1