A baseball diamond is a square with sides 90 ft long. A batter is at bat, with runners at first and second base. At the moment the ball is hit, the runner at first base runs to second base at 25 ft/s. Simultaneously, the runner on second base runs to third base at 15 ft/s. How fast is the distance between these two runners changing 2 s after the ball is hit?

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Answer:

It is changing at -11 ft

Step-by-step explanation:

The distance d is given by

d = √x²+(90-y)²

We have to differentiate

dy/st = 25ft

dx/dt = -15ft

The question says after 2 seconds

Y = 25x2 = 50ft

X = -15x2 = -30ft

Then we calculate rate of change of distance. From the calculations I did, I arrived at

(1/2√900+1600).[900-2000]

= -1100/2x50

= -1100/100

= -11ft

Please check attachment to help you understand the answer better as it is more detailed.

Ver imagen ogorwyne

The distance between these two runners changing 2 s after the ball is hit 11 ft

What is differentiation?

The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.

A baseball diamond is a square with sides 90 ft long.

A batter is at bat, with runners at first and second base.

At the moment the ball is hit, the runner at first base runs to second base at 25 ft/s.

Simultaneously, the runner on second base runs to third base at 15 ft/s.

The distance d is given by

[tex]\rm d = \sqrt{x^{2} +(90-y)^2}[/tex]

We have to differentiate

[tex]\rm \dfrac{dy}{st} = 25 \ ft\\\\\dfrac{dx}{dt} = -15 \ ft[/tex]

The question says after 2 seconds

[tex]\rm Y = 25x ^2 = 50 \ ft\\\\X = -15x^2 = -30 \ ft[/tex]

Then we calculate the rate of change of distance will be

[tex]\rm \dfrac{1 }{2\sqrt{900 + 1600}} * (900 - 2000) = \dfrac{-1100}{2*50} = \dfrac{-1100}{100} = -11\ ft[/tex]

More about the differentiation link is given below.

https://brainly.com/question/24062595

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