Answer:
[tex]\left[\begin{array}{ccc}-3&8&5\\-9&26&11\end{array}\right][/tex]
Step-by-step explanation:
Given the matrix A
[tex]\left[\begin{array}{ccc}-3&8&5\\-1&2&3\end{array}\right][/tex]
We are to find the matrix that results from the elementary row operations represented by −3R2+4R1
R2 means row 2
R1 means row 1
Applying the elementary row operation will change the second row of the matrices.
For the first column, second row (a₂₁)
If R1 = -3, R2 = -1
a₂₁ = -3R2+4R1
a₂₁ = -3(-1)+4(-3)
a₂₁ = 3-12
a₂₁ = -9
For a₂₂
If R1 = 8, R2 = 2
a₂₂ = -3R2+4R1
a₂₂ = -3(2)+4(8)
a₂₂ = -6+32
a₂₂ = 26
For a₂₃
If R1 = 5, R2 = 3
a₂₃ = -3R2+4R1
a₂₃ = -3(3)+4(5)
a₂₃ = -9+20
a₂₃ = 11
Hence the resulting matrix will be:
[tex]\left[\begin{array}{ccc}-3&8&5\\-9&26&11\end{array}\right][/tex]-3R2+4R1
