Answer: Choice A) [tex]3 \sqrt{26}[/tex]
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Work Shown:
[tex]\text{The two points are } (x_1,y_1) = (6,7) \text{ and } (x_2,y_2) = (3,-8)\\\\d = \text{Distance between } (x_1,y_1) \text{ and } (x_2,y_2)\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} = \text{Distance Formula}\\\\d = \sqrt{(6-3)^2+(7-(-8))^2}\\\\d = \sqrt{(6-3)^2+(7+8)^2}\\\\[/tex]
[tex]d = \sqrt{(3)^2+(15)^2}\\\\d = \sqrt{9+225}\\\\d = \sqrt{234}\\\\d = \sqrt{9*26}\\\\d = \sqrt{9}*\sqrt{26}\\\\d = 3\sqrt{26}\\\\[/tex]
When going from 234 to 9*26, the idea here is to factor where one factor is the largest perfect square possible. That way we can use the rule [tex]\sqrt{x*y} = \sqrt{x}*\sqrt{y}[/tex] to break up the root and simplify.
