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Answer:

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Step-by-step explanation:

cc HB buggy CFB

The value of "x" will be "7".

Given:

  • [tex]m_2 = 6x+8[/tex]
  • [tex]m_6=8x-6[/tex]

When "m" is parallel, then

→      [tex]m_2=m_6[/tex]

By substituting the values, we get

→ [tex]6x+8=8x-6[/tex]

By adding "6" both sides, we get

→ [tex]6x+8+6=8x-6+6[/tex]

→      [tex]6x+14=8x[/tex]

By subtracting "6x" from both sides, we get

→  [tex]6x+14-6x=8x-6x[/tex]

→                   [tex]14=2x[/tex]

                      [tex]x = \frac{14}{2}[/tex]

                          [tex]= 7[/tex]

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