Answer:
[tex]P=1.23atm[/tex]
Explanation:
Hello.
In this case, since the total pressure in the container includes the pressures of both hydrogen and water:
[tex]P=P_{H_2}+P_{H_2O}[/tex]
For the reacting solution of HCl, based on the 6:3 mole ratio with hydrogen in the chemical reaction, we can next compute the yielded moles o hydrogen:
[tex]n_{H_2}=0.235L*1.50\frac{molHCl}{L}*\frac{3molH_2}{6molHCl} =0.176molH_2[/tex]
Then, by using the ideal gas equation we compute the pressure of hydrogen for the collected 3.60 L at 25.0 °C (298.15 K):
[tex]P_{H_2}=\frac{n_{H_2}RT}{V} =\frac{0.176mol*0.082\frac{atm*L}{mol*K}*298.15K}{3.60L}=1.20atm[/tex]
Finally, since the vapor pressure of water in at is 0.03129, the total pressure is then:
[tex]P=1.20atm+0.03129atm\\\\P=1.23atm[/tex]
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