Respuesta :
Answer: $1.25
Step-by-step explanation:
Let the cost of cracker be a.
Let the cost of cookies be b.
Let the cost of candy bars be c.
From the question,
6a + 6b + 6c = $21
8a + 5b + 10c = $26
5a + 4b + 7c = $18.50
To solve this, we first pick any two pairs of equation. This will be:
6a + 6b + 6c = $21 ....... i
8a + 5b + 10c = $26 ....... ii
Multiply equation i by 8
Multiply equation ii by 6
48a + 48b + 48c = $168 ....... iii
48a + 30b + 60c = $156 ....... iv
Subtract equation iv from iii
18b - 12c = 12
We then pick another two pairs
8a + 5b + 10c = $26
5a + 4b + 7c = $18.50
Multiply equation i by 5
Multiply equation ii by 8
40a + 25b + 50c = $130
40a + 32b + 56c = $148
Subtract the equations
-7b - 6c = -18
Then, solve the new equations formed
18b - 12c = 12 ....... v
-7b - 6c = -18 ....... vi
Multiply equation i by -7
Multiply equation ii by 18
-126b + 84c = -84
-126b - 108c = -324
Subtract the equations
192c = 240
c = 240/129
c = $1.25
From equation v, put the value of c
18b - 12c = 12
18b - 12($1.25) = 12
18b - $15 = $12
18b = $27
b = $27/18
b = $1.5
Since,
6a + 6b + 6c = $21
6a + 6($1.5) + 6($1.25) = $21
6a + $9 + $7.5 = $21
6a + $16.5 = $21
6a = $21 - $16.5
6a = $4.5
a = $4.5/6
a = $0.75
One candy bar cost $1.25
The cost of one candy bar is $1.5 and this can be determined by forming the linear equation with the help of given data.
Given :
- Miss Croft made snack bags for the picnic that contain three types of snacks: packages of crackers, packages of cookies, and candy bars.
- A snack bag containing 6 of each type of snack costs $21.00.
- A snack bag containing 8 packages of crackers, 5 packages of cookies, and 10 candy bars costs $26.00.
- A snack bag containing 5 packages of crackers, 4 packages of cookies, and 7 candy bars costs $18.50.
Form the linear equation in order to determine the cost of one candy bar. Let 'x' be the cost of crackers, 'y' be the cost of cookies, and 'z' be the cost of candy bars.
So, the linear equation that represents the situation "A snack bag containing 6 of each type of snack costs $21.00" is:
6x + 6y + 6z = 21 --- (1)
The linear equation that represents the situation "A snack bag containing 8 packages of crackers, 5 packages of cookies, and 10 candy bars costs $26.00" is:
8x + 5y + 10z = 26 --- (2)
The linear equation that represents the situation "A snack bag containing 5 packages of crackers, 4 packages of cookies, and 7 candy bars costs $18.50" is:
5x + 4y + 7z = 18.50 --- (3)
Simplify all three equations in order to determine the value of 'x', 'y', and 'z'.
z = $1.25
y = $1.5
x = $0.75
For more information, refer to the link given below:
https://brainly.com/question/11897796
