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1 (4 points) A 2-kg ball is moving with a constant speed of 5 m/s in a horizontal circle whose radius is 50 cm. What is the magnitude of the net force on the ball

Respuesta :

Eduard22sly

Answer:

100 N

Explanation:

The following data were obtained from the question:

Mass (m) = 2 Kg

Velocity (v) = 5 m/s

Radius (r) = 50 cm

Force (F) =.?

Next, we shall convert 50 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

50 cm = 50 cm × 1 m / 100 cm

50 cm = 0.5 m

Therefore, 50 cm is equivalent to 0.5 m.

Finally, we shall determine the magnitude of the net force on the ball by using the following formula:

F = mv²/r

Mass (m) = 2 Kg

Velocity (v) = 5 m/s

Radius (r) = 0.5 m

Force (F) =.?

F = mv²/r

F = 2 × 5²/ 0.5

F = 2 × 25/ 0.5

F = 50 / 0.5

F = 100 N

Therefore, the magnitude of the net force on the ball is 100 N.

Cricetus

The magnitude of the net force on the ball will be "100 N".

Force and speed

According to the question,

Mass, m = 2 kg

Velocity, v = 5 m/s

Radius, r = 50 cm or,

               = 50 × [tex]\frac{1}{100}[/tex]

               = 0.5 m

We know the relation,

Force, F = [tex]\frac{mv^2}{r}[/tex]

By substituting the values, we get

              = [tex]\frac{2\times (25)^2}{0.5}[/tex]

              = [tex]\frac{2\times 25}{0.5}[/tex]

              = [tex]\frac{50}{0.5}[/tex]

              = 100 N

Thus the above response is appropriate.

Find out more information about force here:

https://brainly.com/question/6504879

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