This is about division of polynomials.
(f/g)(x) = (x + 1)/(2x + 3)
f(x) = 2x² - 3x - 9
g(x) = 4x² - 9
f(x) = 2x² - 3x + 6x - 9
Let's collect like terms;
f(x) = x(2x - 3) + 1(2x - 3)
Rewriting in factored form gives;
f(x) = (x + 1)(2x - 3)
g(x) = 4x² - 9
g(x) = 4x² + 6x - 6x - 9
g(x) = 2x(2x + 3) - 3(2x + 3)
Rewriting in factored form gives;
g(x) = (2x + 3)(2x - 3)
Thus;
(f/g)(x) = ((x + 1)(2x - 3))/((2x + 3)(2x - 3))
(f/g)(x) = (x + 1)/(2x + 3)
Read more at;
brainly.in/question/37643694