Respuesta :
Answer:
[H3O+] = 0.0440M
[OH-] = 2.27x10⁻¹³M
Explanation:
Based on the equilibrium of water:
2H2O ⇄ H3O+ + OH-
K = 1x10⁻¹⁴ = [H3O+] [OH-] (1)
We can determine [OH-] with [H3O+] or vice versa
As HCl is a strong acid, [HCl] = [H3O+]
That means:
[H3O+] = 0.0440M
And [OH-] is:
1x10⁻¹⁴ / [H3O+] = [OH-]
2.27x10⁻¹³M = [OH-]
Taking into account the definition of pH and pOH, the hydronium ion, H₃O⁺, and hydroxide ion, OH−, are 0.044 M and 2.29×10⁻¹³ M respectively.
First of all, pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
The following relationship can be established between pH and pOH:
pOH + pH= 14
In this case, you have a 0.044 M HCl. HCl is a strong acid.
It is called strong acid, that acid that dissociates completely in solution at constant temperature and pressure. Under these conditions, the concentration of a strong acid is equal to the concentration of hydrogen ions (Hydronium or H₃O⁺). Then, in this case:
[H⁺]= [H₃O⁺]= [HCl]= 0.044 M
Replacing in the definition of pH:
pH= -log (0.044 M)
Solving:
pH= 1.36
Considering the relationship established between pH and pOH:
pOH + 1.36= 14
pOH= 14 -1.36
pOH= 12.64
Finally, replacing in the definition of pOH:
12.64= -log [OH-]
[OH-]= 10⁻¹² ⁶⁴
[OH-]= 2.29×10⁻¹³ M
In summary, the hydronium ion, H₃O⁺, and hydroxide ion, OH−, are 0.044 M and 2.29×10⁻¹³ M respectively.
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