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Answer:

[H3O+] = 0.0440M

[OH-] = 2.27x10⁻¹³M

Explanation:

Based on the equilibrium of water:

2H2O ⇄ H3O+ + OH-

K = 1x10⁻¹⁴ = [H3O+] [OH-] (1)

We can determine [OH-] with [H3O+] or vice versa

As HCl is a strong acid, [HCl] = [H3O+]

That means:

[H3O+] = 0.0440M

And [OH-] is:

1x10⁻¹⁴ / [H3O+] = [OH-]

2.27x10⁻¹³M = [OH-]

Taking into account the definition of pH and pOH, the hydronium ion, H₃O⁺, and hydroxide ion, OH−, are 0.044 M and 2.29×10⁻¹³ M respectively.

First of all, pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pOH + pH= 14

In this case, you have a 0.044 M HCl.   HCl is a strong acid.

It is called strong acid, that acid that dissociates completely in solution at constant temperature and pressure. Under these conditions, the concentration of a strong acid is equal to the concentration of hydrogen ions (Hydronium or H₃O⁺). Then, in this case:

[H⁺]=  [H₃O⁺]= [HCl]= 0.044 M

Replacing in the definition of pH:

pH= -log (0.044 M)

Solving:

pH= 1.36

Considering the relationship established between pH and pOH:

pOH + 1.36= 14

pOH= 14 -1.36

pOH= 12.64

Finally, replacing in the definition of pOH:

12.64= -log [OH-]

[OH-]= 10⁻¹² ⁶⁴

[OH-]= 2.29×10⁻¹³ M

In summary, the hydronium ion, H₃O⁺, and hydroxide ion, OH−, are 0.044 M and 2.29×10⁻¹³ M respectively.

Learn more:

  • brainly.com/question/12200689
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