The frictional force that acts on the puck is 0.5 N.
The given parameters;
- coefficient of kinetic friction, μk = 0.1
- normal force of the puck, Fₙ = 5 N
The frictional force that acts on the puck is determined by taking the product of the normal force and the coefficient of kinetic friction.
The frictional force that acts on the puck is calculated as follows;
[tex]F_k = \mu_k F_n[/tex]
Substitute the given parameters in the above equation and solve the frictional force.
[tex]F_k = 0.1 \times 5\\\\F_k = 0.5 \ N[/tex]
Thus, the frictional force that acts on the puck is 0.5 N.
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