Na2SiO3 (s) + 8HF(aq) → H2SiF6 (aq) +2 NaF(aq) + 3H2O (l)

1.How many moles of HF are needed to react with 87.44 mol of Na2SiO3?

2.How many grams of NaF form when 0.94 mol of HF reacts with excess Na2SiO3?

3.How many liters of Na2SiO3 can react with 54.68 g of HF?